In other words you have a /24 network that you want to divide in 6 networks.
Let's reorder the teams by size:
Team 5 : 65 hosts
Team 4 : 32 hosts
Team 2 : 16 hosts
Team 3 : 13 hosts
Team 6 : 12 hosts
Team 1 : 5 hosts
and compare them with subnet sizes:
A /24 network comprise 256 addresses from which you must remove the network, broadcast and gateway addresses leaving 253 addresses for hosts.
Similarly:
/25 : 125 hosts
/26 : 61 hosts
/27 : 29 hosts
/28 : 13 hosts
/29 : 5 hosts
So we see that we need at a minimum:
Team 5 : 65 hosts -> /25
Team 4 : 32 hosts -> /26
Team 2 : 16 hosts -> /27
Team 3 : 13 hosts -> /28
Team 6 : 12 hosts -> /28
Team 1 : 5 hosts -> /29
Can we divide a /24 network to fit all those networks in ?
A way to look at it would be:
Divide the /24 in two /25 networks.
The first /25 is assigned to Team5
, the second /25 is further sub-netted.
Divide the second /25 in two /26 networks.
The first /26 is assigned to Team4
, the second is further sub-netted.
Divide the second /26 in two /27 networks.
The first /27 is assigned to Team2
, the second is further sub-netted.
Divide the second /27 in two /28 networks.
the two /28 are assigned to Team3
and Team6
.
Nothing left for Team1
... ...too bad.
You could for example:
- Group Team 1 with another team (so both team will use the same
network).
- User for another team 2 networks, i.e.:
Separate the the first /25 that was assigned to Team 5 in two /26 networks.
Assign the first one to the first 63 hosts of Team5.
Subnet the second one in four /28 networks
Assign the first /28 to the other members of Team 5, the second one to team 1 and you have two /28 available.