i have to construct a subnet in cisco packet tracer using this ip that was supposedly given by the IPS:
79.48.0.0/16
But when i try to configurate the routing using RIP, and put for example 79.48.2.0 i get in the RIP network addresses 79.0.0.0 (255.0.0.0)
In normal cases, when using for example: 192.168.1.0 it appears correctly, so what it's going on? I'm using a 24 bit mask for 4 subnet
(79.48.0.0, 79.48.1.0, 79.48.2.0, 79.48.3.0)(all using this mask 255.255.255.0)
and a serial cable (10.0.0.0 255.0.0.0)
(here's a example)
/16
network, the correct mask length is/18
, not/24
. – Ron Maupin Jul 06 '16 at 17:13/24
, but your question says you need four subnets, and that is a very different requirement. – Ron Maupin Jul 06 '16 at 17:2879.48.0.0/18
has a mask of255.255.192.0
. You really need to do this in binary, then it becomes obvious. – Ron Maupin Jul 06 '16 at 17:46/24
subnets for a/16
network, not just four subnets. If the requirement is to subnet the/16
network into four subnets, then you use a/18
. Your question is unclear, but it seemed to imply that the requirement was by subnet, not host. – Ron Maupin Jul 06 '16 at 18:13