Well, up to this point I'm a bit confused of how to do IPv6 Subnetting outside nibble boundaries with specific hosts numbers.
Lets say that i have a /64, and that i want to divide it in 3 subnets, 2 WAN and 1 LAN, the LAN needs to be able to handle 2000 hosts, and well, the WANS are 3 hosts wide.
The first thing that i do is to determine how many bits i require,so, for the Wans is 2 bits, and for the lan is 11 bits.
Soo, i will start from the LAN /64+11=/75 :XXXX XXXX XXX0 0000:: So first address will be= 1000:: and last address will be= FFE0:: (from left to right) So, between First and last address there are enough hosts for my LAN
then.. WAN1
first: FFF0::
last: FFF8::
WAN2
first: FFFC::
last: FFFE::
in both WAN cases, i left reserved bits at the right... so for the first i do like this :1111 1111 111X X000:: second: :1111 1111 1111 1XX0::
What i don't really get is then, i have a /75 for LAN1.. /77 for Wan1... /79 for WAN2, which makes no sense at all, as in both cases, that masks can handle LOTS of IP... Then.. based on what i have seen online, is that the mask goes in the opposite way (which makes sense), so instead of a /64 + how many bits, is 128-how many bits... In which case the bits match how many host i want to fit... but all those examples do the "subneting" from right to left.... so its possible to do as i want?
/64
, else you break some IPv6 features. The exceptions are/127
for point-to-point links, and/128
for loopbacks. – Ron Maupin Jan 13 '24 at 20:04